General Mathematics · 2nd secondary · First Term

Real Functions and Graphing Curves — Solving the absolute value equations and inequalities

About this lesson

This unit teaches students how to solve modulus (absolute value) equations and inequalities both graphically and algebraically. It begins by explaining that the solution set of an equation f(x)=g(x) is the set of x-coordinates of the intersection points of the two functions' graphs. Students learn to solve equations like |ax+b|=c by graphing the modulus function and a constant function, then finding intersection points, and also by using the piecewise definition of the modulus function. The unit also covers properties of absolute value, such as |ab|=|a||b| and |a+b|≤|a|+|b|, and then moves to solving inequalities like |x-a|<b or |x-a|>b, both graphically (by comparing curves) and algebraically (using rules like if |x|<a then -a<x<a). A real-life application involving temperature deviation is included. By the end, students should be able to solve modulus equations and inequalities using both methods and apply them to model problems.

Main topics in this lesson

  • Solving modulus equations graphically and algebraically
  • Solving modulus inequalities graphically and algebraically
  • Properties of absolute value
  • Graphical interpretation of solutions as intersections of curves
  • Real-life application of modulus equations (temperature deviation)

Key terms and vocabulary

  • modulus function
  • absolute value
  • equation
  • inequality
  • graphical solution
  • algebraic solution
  • solution set
  • constant function
  • intersecting points
  • properties of absolute value

Questions and answers on Real Functions and Graphing Curves — Solving the absolute value equations and inequalities - practice and revision

Multiple choice questions on this lesson in General Mathematics for 2nd secondary, First Term, with practice exercises for revision and exam preparation.

1

مجموعة حل المعادلة |س + 5| = 2 هي:

  • 1 {-3, -7}
  • 2 {3, 7}
  • 3 {-3, 7}
  • 4 {3, -7}
2

إذا كان منحنى الدالة ص = |س| والمستقيم ص = 4 يتقاطعان في نقطتين، فإن مجموع إحداثيي س لنقطتي التقاطع يساوي:

  • 1 صفر
  • 2 4
  • 3 -4
  • 4 8
3

مجموعة حل المتباينة |س - 3| > 0 هي:

  • 1 ح - {3}
  • 2 ح
  • 3 المجموعة الخالية
  • 4 {3}
4

إذا كانت |أ + ب| = 9 و |أ| = 5 و |ب| = 3، فإن العلاقة الصحيحة هي:

  • 1 |أ + ب| ≤ |أ| + |ب|
  • 2 |أ + ب| > |أ| + |ب|
  • 3 |أ + ب| = |أ| - |ب|
  • 4 |أ + ب| = |أ| × |ب|
5

مجموعة حل المتباينة |2س - 1| ≤ 7 هي:

  • 1 [-3, 4]
  • 2 (-3, 4)
  • 3 [-4, 3]
  • 4 (-4, 3)
6

عدد حلول المعادلة |س| = -3 هو:

  • 1 لا يوجد حل
  • 2 حل واحد
  • 3 حلان
  • 4 ثلاثة حلول

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