1
ما مجموعة حل المتباينة x² - 3x - 10 > 0؟
- 1 ]-∞، -2[ ∪ ]5، ∞[
- 2 ]-2، 5[
- 3 [-2، 5]
- 4 ]-∞، 5[ ∪ ]-2، ∞[
Mathematics · 1st secondary · First Term
Algebra, Relations and Functions — Quadratic Inequalities
About this lesson
This unit covers solving quadratic inequalities in one variable, building on prior knowledge of first-degree inequalities. It introduces the concept of a quadratic inequality, connects it to the related quadratic function, and demonstrates how to find the solution set by studying the sign of the function and representing it on a number line. The unit includes worked examples, exercises, and general exercises for practice. By the end, a student should be able to solve quadratic inequalities and express their solution sets as intervals or unions of intervals.
Main topics in this lesson
- Solving quadratic inequalities in one variable
- Sign study of quadratic functions
- Representing solutions on a number line
Key terms and vocabulary
- Quadratic inequality
- Quadratic function
- Solution set
- Interval
- Number line
- Sign of function
Questions and answers on Algebra, Relations and Functions — Quadratic Inequalities - practice and revision
Multiple choice questions on this lesson in Mathematics for 1st secondary, First Term, with practice exercises for revision and exam preparation.
2
ما مجموعة حل المتباينة x² - 3x - 10 < 0؟
- 1 ]-2، 5[
- 2 ]-∞، -2[ ∪ ]5، ∞[
- 3 [-2، 5]
- 4 ]-5، 2[
3
ما مجموعة حل المتباينة x² - 25 ≤ 0؟
- 1 [-5، 5]
- 2 ]-5، 5[
- 3 ]-∞، -5] ∪ [5، ∞[
- 4 ]-∞، 5]
4
ما مجموعة حل المتباينة x² - 2x - 15 ≥ 0؟
- 1 ]-∞، -3] ∪ [5، ∞[
- 2 [-3، 5]
- 3 ]-3، 5[
- 4 ]-∞، 5] ∪ [3، ∞[
5
ما مجموعة حل المتباينة x² - 6x < 0؟
- 1 ]0، 6[
- 2 ]-∞، 0[ ∪ ]6، ∞[
- 3 [0، 6]
- 4 ]-6، 0[
6
ما مجموعة حل المتباينة x² + 3x > 0؟
- 1 ]-∞، -3[ ∪ ]0، ∞[
- 2 ]-3، 0[
- 3 [-3، 0]
- 4 ]-∞، 0[ ∪ ]3، ∞[
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